Soal :
Nyatakan fungsi Boolean f(a,b,c) = a + b’c dalam bentuk kanonik POS !
Jawaban :
f(a,b,c) = a + b’c
= (a + b’)(a + c)
a + b’ = a + b’ + (c c’)
=(a + b’+ c)(a + b’+c’)
A + c = a + c +(b b’)
=(a + b + c)(a + b’+ c)
Jadi f(a,b,c) = (a + b’+ c)(a + b’+c’)(a + b + c)(a + b’+ c)
= (a + b + c)(a + b’+ c)(a +b’+c’)
= M0M2M3
= π(0,2,3)